4[z-(3z+29)+9]=3(z+10)

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Solution for 4[z-(3z+29)+9]=3(z+10) equation:


Simplifying
4[z + -1(3z + 29) + 9] = 3(z + 10)

Reorder the terms:
4[z + -1(29 + 3z) + 9] = 3(z + 10)
4[z + (29 * -1 + 3z * -1) + 9] = 3(z + 10)
4[z + (-29 + -3z) + 9] = 3(z + 10)

Reorder the terms:
4[-29 + 9 + z + -3z] = 3(z + 10)

Combine like terms: -29 + 9 = -20
4[-20 + z + -3z] = 3(z + 10)

Combine like terms: z + -3z = -2z
4[-20 + -2z] = 3(z + 10)
[-20 * 4 + -2z * 4] = 3(z + 10)
[-80 + -8z] = 3(z + 10)

Reorder the terms:
-80 + -8z = 3(10 + z)
-80 + -8z = (10 * 3 + z * 3)
-80 + -8z = (30 + 3z)

Solving
-80 + -8z = 30 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-80 + -8z + -3z = 30 + 3z + -3z

Combine like terms: -8z + -3z = -11z
-80 + -11z = 30 + 3z + -3z

Combine like terms: 3z + -3z = 0
-80 + -11z = 30 + 0
-80 + -11z = 30

Add '80' to each side of the equation.
-80 + 80 + -11z = 30 + 80

Combine like terms: -80 + 80 = 0
0 + -11z = 30 + 80
-11z = 30 + 80

Combine like terms: 30 + 80 = 110
-11z = 110

Divide each side by '-11'.
z = -10

Simplifying
z = -10

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